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2m^2-600-7m=0
a = 2; b = -7; c = -600;
Δ = b2-4ac
Δ = -72-4·2·(-600)
Δ = 4849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-\sqrt{4849}}{2*2}=\frac{7-\sqrt{4849}}{4} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+\sqrt{4849}}{2*2}=\frac{7+\sqrt{4849}}{4} $
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